Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
65 views
in Chemistry by (84.6k points)
Which is a stronger reducing agent `Cr^(2+)` or `Fe^(2+)` and why?

Please log in or register to answer this question.

1 Answer

0 votes
by (87.2k points)
Correct Answer - In Comparison to `Fe^(2+)` , `Cr^(2+)` is a stronger reducing agent because in formation of `Cr^(3+)` from `Cr^(2+)` changes is from `d^(4)tod^(3)..` In `d^(3)` electronic configuration `t_(20)` orbitals are half filled . But in `Fe^(2+)` to `Fe^(3+)` Changes is `d^(6)` to d^(5) in medium like water `d^(6)` is more stable than `d^(5)` .

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...