Question

Calculate wt of urea which must be dissolved in `400gm` of water so final solutions has `V.P.2%` less than `V.P.` of pure water:

Answer 1

Let `V.P` be `V`. Of water
`P^(0)-P_(s)=0.98 V`
`rArr (0.02)/(0.98)=(w)/(60)xx(18)/(400) ,` where `w=`weight of urea.
`w=(2xx60xx400)/(18xx98)gm`.

Comments

Multiply by 9.8 to get weight, this we got mass