Put x – 3 = X and y – 4 = Y in the given equation, we get,
X2 + XY – 2Y2 = 0
Comparing this equation with ax2 + 2hxy + by2 = 0, we get,
a = 1, h = 1/2, b = -2
This is the homogeneous equation of second degree and h2 – ab = (1/2)2 – 1(-2)
= 1/4 + 2 = 9/4 >0
Hence, it represents a pair of lines passing through the new origin (3, 4).
Let θ be the acute angle between the lines.