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The normal to the curve x^2 + 2xy - 3y^2 = 0 at (1, 1)

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The normal to the curve x2 + 2xy - 3y2 = 0 at (1, 1) 

(a) does not meet the curve again

(b) meets the curve again in the second quadrant

(c) meets the curve again in the third quadrant

(d) meets the curve again in the fourth quadrant

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Best answer

Correct option (d) meets the curve again in the fourth quadrant

Explanation:

On solving Eqs (i) and (ii) simultaneously, we get

Hence, normal meets the curve again at (3, - 1) in fourth quadrant.

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