Question

For the following cell reaction

Pb(s)+ Hg₂SO₄(s) PbSO₄(s) + 2Hg(l) E°_cell = 0.92 V 

K_sp(PbSO₄) = 2 x 10^-8

K_sp(HgSO₄) = 1 x 10^-6

Hence, E_cell is

(a) 0.92 V

(b) 0.89 V

(c) 1.04 V

(d) 0.95 V

Answer 1

Correct Option (d) 0.95 V

Explanation: