Question

If ΔABC ~ ΔDEF, ∠A = 50°, then ∠E + ∠F = ……………… 

(A) 100° 

(B) 125° 

(C) 130° 

(D) 140°

Answer 1

Correct option is (C) 130°

Given that \( \triangle ABC \sim \triangle DEF\)

\(\therefore\) \(\angle D=\angle A=50^\circ\)      (Given \(\angle A=50^\circ)\)

In \(\triangle DEF,\) \(\angle D+\angle E+\angle F=180^\circ\)  (Sum of angles in a triangle)

\(\Rightarrow\) \(\angle E+\angle F=180^\circ-\angle D\)

\(=180^\circ-50^\circ=130^\circ\)

Answer 2

Correct option is: (C) 130°