Question

An inductance of 0.5 H, a capacitor of capacitance `10^(-9)F` and a resistane of `100Omega` are connected in series across AC source of emf 10 V. the current through the circuit at resonance is
A. `1A`
B. `10A`
C. 0.1 A
D. 0.01 A

Answer 1

Correct Answer - C
At resonance, `I=(e)/(R)`
`=(10)/(100)=0.1A`