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A monoprotic acid `(HA)` is `1%` ionised in its aqueous solution of `0.1M` strength. Its `pOH` will be

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A monoprotic acid `(HA)` is `1%` ionised in its aqueous solution of `0.1M` strength. Its `pOH` will be
A. 11
B. 3
C. 10
D. 2
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Correct Answer - A
`[H_(2)O^(+)]=c alpha =0.1 xx (0.01)=1xx10^(-3)`
`:. pH=3` . Hence, `pOH =14-3=11`.
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