Correct option is (A) 1/4
\(\frac{x+y}{xy}=2\;and\;\frac{x-y}{xy}=6\)
\(\Rightarrow\) \(\frac1x+\frac1y=2\) ________(1)
and \(\frac1y-\frac1x=6\) ________(2)
Put \(\frac1x=X\;\&\;\frac1y=Y,\) then equations (1) & (2) converts into
X + Y = 2 ________(3)
Y - X = 6 ________(4)
Adding equations (3) & (4), we get
(X + Y) + (Y - X) = 2+6
\(\Rightarrow\) 2Y = 8
\(\Rightarrow\) Y = \(\frac82\) = 4
\(\therefore\) X = 2 - Y
= 2 - 4 = -2
\(\because\) X = -2
\(\Rightarrow\) \(\frac1x=-2\)
\(\Rightarrow\) \(x=\frac{-1}2\)
and Y = 4
\(\Rightarrow\) \(\frac1y=4\)
\(\Rightarrow\) \(y=\frac14\)