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in Linear Equations by (41.0k points)
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A is twice as old as B, ten years ago. If A was four times as old as B, their present ages are ……………

A) 24 and 12 

B) 30 and 15 

C) 32 and 16 

D) 20 and 10

2 Answers

+1 vote
by (57.0k points)
selected by
 
Best answer

Correct option is (B) 30 and 15

Let A's present age be x years and B's present age be y years.

Since, A is twice as old as B.

\(\therefore\) x = 2y              __________(1)

10 years ages, A's age = (x - 10) years

& B's age = (y - 10) years

Given that 10 years ago, A was four times as old as B.

\(\therefore\) x - 10 = 4 (y - 10)

\(\Rightarrow\) 2y - 10 = 4y - 40    (From (1))

\(\Rightarrow\) 4y - 2y = 40 - 10

\(\Rightarrow\) 2y = 30

\(\Rightarrow\) y = \(\frac{30}2\) = 15

\(\therefore\) x = 2 \(\times\) 15 = 30     (From (1))

Hence, their present ages are 30 and 15 years.

+1 vote
by (37.4k points)

Correct option is B) 30 and 15

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