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If xy = e^(x - y), then prove that dy/dx = (log x)/(1 + log x)^2

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If xy = ex - y, then prove that dy/dx = (log x)/(1 + log x)2

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1 Answer

+1 vote
by (30.7k points)

Given,

xy = ex - y 

On taking log both sides, we get

On differentiating both sides w.r.t. x, we get

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