Correct option is (D) ₹ 150, ₹ 15
Let initial salary of the employee be Rs a. And incriment in his salary by Rs d.
Given that his monthly salary is in A.P.
Also given that \(a_{11}=300\;\&\;a_{24}=495\)
\(\therefore a+10d=300\) ________________(1)
& \(a+23d=495\) ________________(2)
Subtract equation (1) from (2), we get
\(a+23d-(a+10d)=495-300\)
\(\Rightarrow13d=195\)
\(\Rightarrow d=\frac{195}{13}=15\)
\(\therefore\) Incriment is Rs 15.
Put d = 15 in equation (1), we get
\(a+150=300\)
\(\Rightarrow a=300-150=150\)
\(\therefore\) Employee's initial salary is Rs 150.
