Correct option is (C) (-3, -2)
Let centre of the circle is O(0, 0) and its end points of diameter are \(A(3,2)\;\&\;B(x,y).\)
\(\therefore\) O is mid-point of AB
\((\because\) Centre of the circle is mid-point of the diameter)
\(\therefore\) Coordinates of point O is \((\frac{3+x}2,\frac{2+y}2)=(0,0)\)
\(\Rightarrow\frac{3+x}2=0\;and\;\frac{2+y}2=0\) (By comparing x & y-coordinates of point O)
\(\Rightarrow x=2\times0-3\;and\;y=2\times0-2\)
\(\Rightarrow x=-3\;and\;y=-2\)
Hence, other end point is \(B(x,y)=(-3,-2).\)
