Correct Answer - B
Heat liberated by the combustion of 1 mol bezoic acid i.e., 122 g benzoic acid
`q=msDeltaT`
`=18940xx0.998xx0.632`
`=11946.14cal`
Heat liberated by the combustion of 1 mol benzoic acid ie.., 122 g benzoic acid
`=(11946.14)/(1.89)xx122=771126.5cal`
`=771.12" kcal "mol^-1`