Question

The pressure-volume of varies thermodynamic process is shown in graphs:

Work is the mole of transference of energy. It has been observed that reversible work done by the system is the maximum obtainable work.
`w_(rev) gt w_(irr)`
The works of isothermal and adiabatic processes are different from each other.
`w_("isothermal reversible") = 2.303 nRT log_(10) ((V_(2))/(V_(1)))`
`= 2.303 nRT log_(10)((P_(2))/(P_(1)))`
`w_("adiabatic reversible") = C_(V) (T_(1)-T_(2))`
The `q` value and work done in isothermal reversible expansion of one mole of an ideal gas from initial pressure of `1` bar to final pressure of `0.1` bar at constant temperature `273K` are:
A. 5.22 kJ, -5.22 kJ
B. `-5.22kJ,5.22kJ`
C. `5.22kJ,5.22kJ`
D. `-5.22kJ,-5.22kJ`

Answer 1

Correct Answer - A
Slope of the adiabatic curve `propgamma`
Slope of `Bgt` Slope of A
`He(gamma=1.66)," "O_(2)(gamma=1.44)`. Thus, correct answer will be (c).