(i) Given: n = 10 and p = 0.4
∴ q = 1 – p = 1 – 0.4 = 0.6
∴ E(X) = np = 10(0.4) = 4
Var(X) = npq = 10(0.4)(0.6) = 2.4
Hence, E(X) = 4, Var(X) = 2.4.
(ii) Given: p = 0.6, E (X) = 6
E(X) = np
6 = n(0.6)
n = 6/0.6 = 10
Now, q = 1 – p = 1 – 0.6 = 0.4
∴ Var(X) = npq = 10(0.6)(0.4) = 2.4
Hence, n = 10 and Var(X) = 2.4.
(iii) Given: n = 25, E(X) = 10
E(X) = np
10 = 25p
(iv) Given: n = 10, E(X) = 8
E(X) = np
8 = 10p