Volume of `N_(2)` at 1 atm, 273 K required to form a monolayer on the surface of iron catalyst is `8.15ml//gm` of the adsorbent. What will be the surface area of the adsorbent per gram if each nitrogen molecule occupies `16 xx 10^(-22)m^(2)`?
[Take : `N_(A)=6xx10^(23)`]
A. `16 xx 10^(-16)cm^(2)`
B. `0.35 m^(2)//g`
C. `39 m^(2)//g`
D. `22400 cm^(2)`
