Question

Determine an AP whose third term is 9 and when fifth term is subtracted from 8th term, we get 6.

Answer 1

Here given, 

a₃ = 9 

⇒ a + 2d = 9 ....(i) 

a₈ – a₅ = 6 

⇒ (a + 7d) – (a + 4d) = 6 

⇒ 3d = 6 

⇒ d = 2 ....(ii)

Substituting (ii) in (i), we get 

⇒ a + 2(2) = 9 

⇒ a = 5

So, AP is 5, 7, 9, 11, ......