Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
3.6k views
in Chemistry by (106k points)

The elements of the second period of the Periodic Table are given below:
Li, Be, B, C, N, O, F
(i) Explain why atomic radius decreases from Li to F.
(ii) Identify the most metallic and non-metallic elements among the above elements.

1 Answer

+1 vote
by (323k points)
edited by
 
Best answer

(i) On moving from left to right along a period of the Periodic Table, atomic number increases, i,e., number of protons and electrons increases which ultimately increases the nuclear charge. Hence, the electrons are pulled in closer to the nucleus which leads to contraction of the atom and thus atomic radius is decreased.
(ii) On moving from left to right in a Periodic Table, metallic character decreases and non-metallic character increases. This is because the capacity to lose electrons from outermost orbit of an atom (called ionisation energy) decreases. Hence, among the above elements, Li being placed on extreme left side is most metallic and F being placed on extremely right side is most non-metallic element.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...