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A line is drawn through a fix point P(`alpha, beta`) to cut the circle `x^2 + y^2 = r^2` at A and B. Then PA.PB is equal to :
A. `(alpha + beta)^(2)-r^(2)`
B. `alpha^(2)+beta^(2)-r^(2)`
C. `(alpha-beta)^(2)+r^(2)`
D. none of these

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1 Answer

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Correct Answer - B

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