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Making use of the tables of atomic masses, find the velocity with which the products of the reaction B10 (n, α) Li7 come apart; the reaction proceeds via interaction of very slow neutrons with stationary boron nuclei.

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The reaction is B10 (n, α) Li7 . The energy of the reaction is

Since the incident neutron is very slow and B10 is stationary, the final total momentum must also be zero. So the reaction products must emerge in opposite directions. If their speeds are, respectively, vα and vLi 

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