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in Physics by (75.2k points)

Thermal neutrons fall normally on the surface of a thin gold foil consisting of stable Au197 nuclide. The neutron flux density is J = 1.0.1010 part./(s. cm2). The mass of the foil is in = 10 mg. The neutron capture produces beta-active Au188 nuclei with half-life T = 2.7 days. The effective capture cross-section is σ = 98 b. Find: 

(a) the irradiation time after which the number of Au187 nuclei decreases by η = 1.0%; 

(b) the maximum number of Au198 nuclei that can be formed during protracted irradiation.

1 Answer

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Best answer

(a) Suppose N0 = no. of Au197 nuclei in the foil. Then the number of Au197 nuclei transformed in time t is

For this to equal ηN0 , we must have

(b) Rate of formation of the Au198 nuclei is N0 • J • σ per sec and rate of decay is λn, where n is the number of Au198 at any instant.

because if n is smaller,  and n increase further and if n is larger and n will decrease. (Actually nmax is approached steadily as t ∞) Substitution gives using

 

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