Question

Two metal wires ‘P’ and ‘Q’ of same length and material are stretched by same load. Their masses are in the ratio m₁ : m₂. The ratio of elongations of wire ‘P’ to that of ’Q’ is

(A) \(m^2_1:m^2_2\)

(B) \(m^2_2:m^2_1\)

(C) m₂ : m₁

(D) m₁ : m₂

Answer 1

(C) m₂ : m₁

Since m = ρV

= ρ × A × t