Correct option is (D) R.H.S.
In triangles \(\triangle DCB\;and\;\triangle EBC,\)
\(\angle BCD=\angle CEB\) (Right angle)
BC = BC (Common side)
BD = CE (Given both altitudes are equal)
\(\therefore\) \(\triangle DCB\cong \triangle EBC\) (By RHS congruence criteria)