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in Quadrilaterals by (36.7k points)
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From the adjacent figure, PQ || RS, ∠RPQ = 52°, ∠RPS = 65°, ∠PSR = x° and ∠PRQ = 3y° + 5, then the value of x + y is

A) 115° 

B) 137°

C) 200° 

D) 74°

2 Answers

+1 vote
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Best answer

Correct option is (D) 74°

\(\because\) \(PQ\,||\,RS\)

\(\therefore\) \(x^\circ+65^\circ+52^\circ=180^\circ\)

\(\Rightarrow\) \(x^\circ=180^\circ-65^\circ-52^\circ\)

\(\Rightarrow\) \(x^\circ=180^\circ-117^\circ\)

\(\Rightarrow\) \(x^\circ=63^\circ\)

In \(\triangle PQR,\)

\(52^\circ+90^\circ+(3y+5)^\circ=180^\circ\)    (Sum of interior angle in a triangle is \(180^\circ)\)

\(\Rightarrow\) \(3y+147^\circ=180^\circ\)

\(\Rightarrow\) \(3y=180^\circ-147^\circ=33^\circ\)

\(\Rightarrow\) \(y=\frac{33^\circ}3=11^\circ\)

\(\therefore\) \(x+y=63^\circ+11^\circ=74^\circ\)        

+1 vote
by (38.9k points)
edited by

Correct option is  D) 74°

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