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If A(1, 3) and B(2, 1) are points, find the equation of the locus of point P such that PA = PB.

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Let P(x, y) be any point on the required locus. Given, A(1, 3), B(2, 1) and PA = PB 

∴ PA2 = PB2 

∴ (x – 1)2 + ( y – 3)2 = (x – 2)2 + (y – 1)2 

∴ x2 – 2x + 1 + y2 – 6y + 9 = x2 – 4x + 4 + y2 – 2y + 1 -2x – 6y + 10 = -4x – 2y + 5 

∴ 2x – 4y + 5 = 0 

∴ The required equation of locus is 2x – 4y + 5 = 0.

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