Question

Find the equation of the line having inclination 135° and making x-intercept 7.

Answer 1

Given, Inclination of line = 0 = 135° 

∴ Slope of the line (m) = tan 0 = tan 135° 

= tan (90° + 45°) 

= – cot 45° = – 1 x-intercept of the required line is 7.

∴ The line passes through (7, 0). Equation of the line in slope point form is y₁ – y = m(x – x₁)

∴ The equation of the required line is y — 0 = – 1 (x – 7) 

∴ y = -x + 7 

∴ x + y – 7 = 0

Answer 2

y= aX+b:-->, where a is the slope of the line and b, is the y-intercept.
when x takes a value of 0 then aX = 0 and then y =b (that's why b is the y-intercept ).

Accordingly, calculate the slope which is tan(theta) ( sin(theta)/cos(theta)= y/x)

put that value to be the (a) in the equation, and put the y-intercept (+7) in place of b

 final eq--> y= tan(135)X+7