Equations of the given parallel lines are 4x – 3y + 5 = 0 and 4x – 3y + 1 = 0
Here, a = 4, b = – 3, c = 5 and c = 7
∴ Distance between the parallel lines
\(=\begin{vmatrix}\frac{c_1-c_2}{\sqrt{a^2+b^2}}\end{vmatrix}\)\(=\begin{vmatrix}\frac{5-7}{\sqrt{4^2+(-3)^2}}\end{vmatrix}\)
\(=\begin{vmatrix}\frac{-2}{\sqrt{16+9}}\end{vmatrix}\)\(=\begin{vmatrix}\frac{-2}{5}\end{vmatrix} = \frac {2}{5} units\)
