Equation of a line having slope ‘m’ and y-intercept ‘c’ is y = mx + c
Given, m = 3, c = 4
The equation of the line is y = 3x + 4
3x – y = -4
\(\frac {3x}{(-4)} - \frac {y}{-4} =1\)
\(\frac {x}{(\frac{-4}{3})} - \frac {y}{4} =1\)
This equation is of the form x/a + y/b =1
where x-intercept = a
x-intercept = -4/3
Alternate Method:
Let θ be the inclination of the line.
Then tan θ = 3 …..[∵ slope = 3 (given)]
OB/ OA = 3
4/ OA = 3
OA = 4/3
x-intercept = - 4/3 as point A is to the left side of Y-axis.
