Given, A(1, 0), B(2, 3) Slope of AB = 3-0/ 2-1 = 3
Required line is perpendicular to AB.
Slope of required line = -1/3
Let point C divide AB in the ratio 1 : 2.
Required line passes through (4/3, 1) and has slope = -1/3
Equation of the line in slope point form is y – y = m(x – x )
The equation of the required line is y-1 = -1/3 (x- 4/3)
⇒ 3(y – 1) = -1 (x - 4/3)
⇒ 3y – 3 = -x + 4/3
⇒ 9y – 9 = -3x + 4
⇒ 3x + 9y = 13
