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0 votes
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in Mathematics by (600 points)

Pls answer my 2 question

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1 Answer

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by (1.4k points)

let P of 1st campaign be : 4/10

let P of 2nd campaign be: 1/5

let P of 3rd campaign be: x

4/10 + 1/5 + x = 1

x = 4/10 = 2/5

therefore, P of 3rd campaign is 2/5

Also given that if the number of persons in second campaign was 20, so

20/(Total number of person involved) = 1/5

Total number of person involved = 20 x 5 = 100

Therefore, Total number of person involved in three campaigns is 100.

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