Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.8k views
in Limits by (42.5k points)
closed by

Evaluate the following limits:

\(\lim\limits_{x\longrightarrow 1}[\frac{2^{2x-2}-2^x+1}{sin^2(x-1)}]\)

lim [22x-2-2x+1/sin2(x-1)] (x ∈ 1) 

1 Answer

+1 vote
by (43.0k points)
selected by
 
Best answer

\(\lim\limits_{x\longrightarrow 1}\frac{2^{2x-2}-2^x+1}{sin^2(x-1)}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...