Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
826 views
in Physics by (32.7k points)
closed by

A ray of light is incident on a water surface of refractive index 4/3 making an angle of 40° with the surface. Find the angle of refraction.

1 Answer

+1 vote
by (32.9k points)
selected by
 
Best answer

Data : n = \(\frac43\)

i = 90\(^\circ\) - 40\(^\circ\) = 50\(^\circ\)

n = \(\cfrac{sin\,i}{sin\,r}\)

\(\therefore\) sin r = \(\cfrac{sin\,i}{n}\) = \(\cfrac{sin\,50^\circ}{4/3}\)

\(\cfrac{0.7660}{4/3}\)

∴ The angle of refraction, r = sin-1 (0.5745) = 35°4′

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...