Correct option (c) there exists at least one x ∈ (1, 3) such that f"(x) = 2
Explanation :
Let, g(x) = f(x) - x2
g(x ) has at least 3 real roots which are x = 1, 2, 3 (by mean value theorem)
g(x) has at least 2 real roots in x ∈ (1, 3)
g "(x) has at least 1 real roots in x ∈ (1, 3)
f "(x) - 2.1 = 0 for at least 1 real root in x ∈ (1, 3)
f ''(x) = 2, for at least one root in x ∈ (1, 3 )