Correct option
(a) continuous at x = 0
(b) continuous in (-1, 0)
(d) differentiable in (-1, 1)
Explanation :
Also, (x sin pi x) becomes negative and numerically less than 1 when x is slightly greater than 1 and so by definition of [x]
Thus, f(x) is constant and equal to 0 in the closed interval [-1, 1] and so f(x) is continuous and differentiable in the open Interval (-1, 1).