Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
23.2k views
in Mathematics by (34.4k points)

If f (x) = min {1, x2, x3 } then

(a) f(x) is continuous everywhere

(b) f(x) is continuous and differentiable everywhere

(c) f(x) is not differentiable at two points

(d) f(x) is not differentiable at one point

1 Answer

+2 votes
by (24.1k points)
selected by
 
Best answer

Correct option 

(a) f(x) is continuous everywhere

(d) f(x) is not differentiable at one point

Explanation :

Here, f (x) = min {1, x2, x3 } which could be graphically shown as

f(x) is continuous for x  R and not differentiable at

x = 1 due to sharp edge.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...