Correct Answer - Option 2 :
\(\frac{1}{2}\)
If the system of equations has non-trivial solutions, then the determinant of coefficient matrix is zero
\(\left| {\begin{array}{*{20}{c}} 1&{ - c}&{ - c}\\ c&{ - 1}&c\\ c&c&{ - 1} \end{array}} \right| = 0\)
No need to apply property just simplification is done.
⇒ 1(1 – c2) + c(– c – c2) – c(c2 + c) = 0
⇒ (1 + c) (1 – c) – 2c2(1 + c) = 0
⇒ (1 + c) (1 – c – 2c2) = 0
⇒ (1 + c) (1 + c) (1 – 2c) = 0
⇒ (1 + c)2 (1 – 2c) = 0
\({\rm{c}} = - 1{\rm{\;or\;}}\frac{1}{2}\)
Hence, the greatest value of
\(c{\rm{\; = \;}}\frac{1}{2}\;\)for which the system of linear equations has non-trivial solution.