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+1 vote
32.8k views
in Mathematics by (130k points)

Maximise Z = 5x + 3y
subject to 3x+5y≤15, 5x+2y≤10,x≥0,y≥0.

1 Answer

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by (93.9k points)
edited by
 
Best answer

The feasible region determined by the system of constraints, 3x + 5y ≤ 15, 5x + 2y ≤ 10, x ≥ 0, and y ≥ 0, are as follows.​

The corner points of the feasible region are O (0, 0), A (2, 0), B (0, 3), and C(20/19,45/19)
The values of Z at these corner points are as follows.

Therefore, the maximum value of Z is 235/19 at the point (20/19,45/19)

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