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How many 3 digit numbers can be formed from the digits 1, 2, 3, 5 which are divisible by 2, when repetition is not allowed?


1. 3
2. 12
3. 6
4. 18

1 Answer

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Correct Answer - Option 3 : 6

Given:

The given digits are 1, 2, 3 and 5

Concept used:

If the last number should be even, then the entire number is divisible by 2

Calculation:

Since each desired number is divisible by 2, so we must have 2 at the unit place.

The Number of ways to fill unit place = 1

Tens place can be filled by any of the remaining 3 digits (1, 3, and 5)

The Number of ways to fill tens place = 3

The hundreds place can be filled by any remaining 2 digits

The Number of ways to fill hundreds place = 2

Number of ways = 1 × 3 × 2 = 6

Total 3 digits number can be formed is 6

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