Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
56 views
in Aptitude by (111k points)
closed by
A man walking in a railway tunnel for repairing starts running in the opposite direction after getting a signal of a train having a speed of 162 km/hr coming towards him. What should be the minimum speed so that he may reach at exit point before the train which is 400 m away from him and 9 km away from the train?
1. more than 8 m/sec
2. more than 4 m/sec
3. more than 1 m/sec
4. more than 2 m/sec

1 Answer

0 votes
by (105k points)
selected by
 
Best answer
Correct Answer - Option 4 : more than 2 m/sec

Given,

Speed of train = 162 km/hr

Distance between train and exit point = 9 km

Formula used, Time = Distance/Speed

Calculation 

Speed of train = 162 km/hr

= 162 × (5/18) m/sec = 45 m/sec

Distance between train and exit point = 9 km

= 9000 metres

Time is taken by train to reach exit point = Distance between train and exit point/Speed

= 9000/45 = 200 seconds

To reach the exit point, man should take less than 200 seconds

Speed of man = 400/200 = 2 m/sec

∴ Speed of man should be more than 2 m/sec

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...