1.Equivalent Resistance between BE, (1Ω, 2Ω, 3Ω are in series) is R1
R1 = 1 + 2 + 3 = 6Ω
R1 is in parallel to R2 = 3Ω their resultant R.3 1/r3 = 1/r1 +1/r2 = 1/6 + 1/3 = 1+2/6 = 1/6 Between BE
∴ R3 = 2Ω
(ii) Equivalent resistance between A and F i.e. R4 , R2 , Rs are in series
3Ω, 2Ω and 3Ω are in series
R= 3 + 2 + 3 = 812