Correct Answer - Option 2 : Increase
Concept:
The voltage of primary of the transformer is,
\(V_1 = 4.44\times f\times \phi_m\times N_1\)
The voltage of secondary of the transformer is,
\(V_2 = 4.44\times f\times \phi_m\times N_2\)
Where,
N1 is the number of turns of the primary
N2 is the number of turns of secondary
f is the supply frequency
ϕm is the flux
As we know that,
kVA rating is the multiplication of voltage and current.
kVA = V × I
As we know the kVA ∝ V
And V ∝ f
As the increase in frequency, the kVA rating is also increasing.
The frequency is inversely proportional to the size of the transformer.
\(f \propto \frac{1}{Size}\)
As the increase in the frequency then the size of the transformer decreases and vice-versa.