Question

A uniform body of 4 m long, 1 m wide, and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body is
1. 20.54 kN
2. 23.54 kN
3. 35.54 kN
4. 45.54 kN

Answer 1

Correct Answer - Option 2 : 23.54 kN

Concept:

Principle of floatation: 

For a body floating in a fluid, the weight of the body must be balanced by buoyant force.

Weight (W) = Buoyant force (FB) = ρ × g × V

where, ρ = density of the fluid, V = Volume of immersion

Calculation:

Given:

L = 4 m, B = 1 m, and H = 1 m

Depth of immersion = 0.6 m

Fore a body to float, weight should be equal to buoyant force.

W = FB

FB = Density of water (ρ) × g × volume of immersion (V)

FB = 1000 × 9.81 × 4 × 1 × 0.6 = 23544 N = 23.544 kN

The weight of the body is 23.544 kN.

Thus, option 2 is the correct answer.