Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
72 views
in Trigonometry by (239k points)
closed by
In Sin3θ = cos(θ - 26°), where 3θ and (θ - 26°) are acute angles, then value of θ 
1. 30°
2. 27°
3. 26°
4. 29°

1 Answer

0 votes
by (237k points)
selected by
 
Best answer
Correct Answer - Option 4 : 29°

Given

sin 3θ = cos(θ - 26°)

Formula Used 

sinθ = cos(90° - θ)

cos θ = sin(90° - θ)

Calculation 

sin 3θ = sin [90° - (θ - 26°)]

⇒ 3θ = 90° - (θ - 26°)

⇒ 4θ = 116° 

⇒ θ = 29° 

∴ The answer is 29° 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...