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The 6th term of an AP is 99. If the 1st term increase by 1 and the common difference decrease by 2 then the 6th term so obtained would be equal to the 5th term of the original AP. Find the 3rd term of this AP.
1. 69
2. 72
3. 75
4. 77

1 Answer

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Correct Answer - Option 2 : 72

Given:

The 6th term of an AP is 99. If the 1st term increases by 1 and the common difference decrease by 2 then the 6th term so obtained would be equal to the 5th term of the original AP.

Formula used:

Nth term of an AP, Tn = a + (n - 1)d, where ‘a’ is the first term, ‘n’ is the total number of terms and ‘d’ is the common difference.

Calculation:

Let the first term is ‘a’ and common difference is‘d’.

From the question

T6 = 99

⇒ a + 5d = 99     ----(1)

After increasing ‘a’ by 1 and decreasing‘d’ by 2 we get,

6th term of New AP = 5th term of original AP

⇒ (a + 1) + 5 × (d - 2) = a + 4d

⇒ a + 5d - 9 = a + 4d

⇒ d = 9

After putting value of ‘d’ in equation (1) we get,

a = 54

Third term of AP = a + 2d

⇒ 54 + 2 × 9 = 54 + 18 = 72

∴ required answer is 72.

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