Correct Answer - Option 4 : 20
Given:
The 21st term of an AP is 172. The 12th term of the AP is 16 less than the 14th term.
Formula used:
nth term of an AP, Tn = a + (n - 1)d, where ‘a’ is the first term, ‘n’ is the total number of terms and ‘d’ is the common difference.
Calculation:
Let the first term is ‘a’ and common difference is‘d’.
T21 = a + 20d = 172 ----(1)
According to question
T14 – T12 = 16
⇒ (a + 13d) - (a + 11d) = 16
⇒ 2d = 16
⇒ d = 8
And from equation (1)
a = 12
Second term T2 = a + d
⇒ 12 + 8 = 20
∴ Required answer is 20.