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The ratio of the amplitude of the magnetic field to the amplitude of the electric field for electromagnetic wave propagation in a vacuum is equal to
1. Unity
2. Speed of light in vacuum
3. Reciprocal of the speed of light in vacuum
4. The ratio of magnetic permeability to electrical susceptibility in a vacuum.

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Correct Answer - Option 3 : Reciprocal of the speed of light in vacuum

Concept:

In electromagnetic waves, the ratio of amplitudes of the electric field and the magnetic field is equal to the velocity of the electromagnetic waves in free space.

\(\frac{{{E_0}}}{{{B_0}}} = c\)

\(\frac{{{B_0}}}{{{E_0}}} = \frac{1}{c}\)

Where:

E0 = Electric field

B0 = Magnetic field

c = velocity

Derivation:

The intrinsic impedance of the wave is defined as the ratio of the electric field and the magnetic field phasor (complex amplitude), i.e.

\(\frac{{\left| E \right|}}{{\left| H \right|}} = \eta = \sqrt {\frac{\mu }{\epsilon}} \)

Since B = μ H

\(H = \frac{B}{\mu }\)

\(\frac{{\left| E \right|}}{{\left| B \right|}}\mu = \sqrt {\frac{\mu }{\epsilon}}\)

\(\frac{{\left| E \right|}}{{\left| B \right|}} = \sqrt {\frac{1}{{\mu\epsilon }}}\)

\(c = \frac{1}{{\sqrt {{\mu _0}{\epsilon_o}} }},\;\frac{{\left| E \right|}}{{\left| B \right|}} = c\)

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