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The interior angles of a pentagon are x°, (x - 10)°, (x + 20)°, (2x - 44)°, and (2x - 70)°. Then find the value of x.
1. 93° 
2. 92° 
3. 104° 
4. 78° 

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Correct Answer - Option 2 : 92° 

Given

The angles of a pentagon are x°, (x - 10)°, (x + 20)°, (2x - 44)°, and (2x - 70)°

Concept

Sum of all interior angles of a regular polygon = (n - 2) × 180° 

Calculation

⇒ n = 5 

⇒ Sum of all interior angles of a regular polygon = (5 - 2) × 180° 

⇒ Sum of all interior angles of a regular polygon = 3 × 180° 

⇒ Sum of all interior angles of a regular polygon = 540° 

Now,

⇒ x + (x - 10)° + (x + 20)° + (2x - 44)° + (2x - 70)° = 540

⇒ x + x - 10° + x + 20° + 2x - 44° + 2x - 70° = 540° 

⇒ (x + x + x + 2x + 2x) + (20° - 10° - 44° - 70°) = 540° 

⇒ 7x - 104° = 540° 

⇒ 7x = 540° + 104° 

⇒ 7x = 644° 

⇒ x = (644°/7)

⇒ x = 92° 

∴ x is 92° 

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