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Find the value of p, if  \({\log _7}\sqrt {7\sqrt {7\sqrt {7\sqrt {.........\infty } } } } = p\).


1. 7
2. 1
3. 2
4. 3

1 Answer

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Best answer
Correct Answer - Option 2 : 1

CONCEPT:

  • Log x (x) = 1

 

CALCULATION:

Given \({\log _7}\sqrt {7\sqrt {7\sqrt {7\sqrt {.........\infty } } } } = p\)

Let  \(\sqrt {7x} = x\)

On squaring we get - 

7x = x2

⇒ x = 7

So, log 77 = 1

⇒  p = 1

Therefore, option (2) is the correct answer.

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