Correct Answer - Option 2 : 1
CONCEPT:
CALCULATION:
Given \({\log _7}\sqrt {7\sqrt {7\sqrt {7\sqrt {.........\infty } } } } = p\)
Let \(\sqrt {7x} = x\)
On squaring we get -
7x = x2
⇒ x = 7
So, log 77 = 1
⇒ p = 1
Therefore, option (2) is the correct answer.