Correct Answer - Option 3 : 1.98 mA and 2 mA
Concept:
Collector current can be calculated as:
Ic = βIb ----(1)
where β is common emitter DC gain and
\(β=\frac{\alpha}{1-\alpha}\) -----(2)
Emitter current can be calculated by:
Ie = Ib + Ic -----(3)
Calculation:
Given:
α = 0.99
Ib = 20 μA
From equation (1) and (2),
Ic can be calculated:
\(\beta=\frac{0.99}{1-0.99}=99\)
Ic = 99 × 20
Ic = 1.98 mA
From equation (3)
Ie can be calculated as:
Ie = 1.98 + 0.02 = 2 mA.